电脑技术学习

SCO UNIX下的时间问题

dn001


struct tm *ltm;
int QSSJ_y,QSSJ_m,QSSJ_d,QSSJ_h,QSSJ_f,QSSJ_s;
long cur_time,Intime,QSSJ_SC;
char firsttime[30],tmp2[255];

time(&cur_time);
ltm=localtime(&cur_time);
sprintf(firsttime, "%04d%02d%02d%02d%02d%02d",
ltm->tm_year+1900,
ltm->tm_mon+1,
ltm->tm_mday,
ltm->tm_hour,
ltm->tm_min,
ltm->tm_sec);

QSSJ_y=ltm->tm_year+1900;
QSSJ_m=ltm->tm_mon+1;
QSSJ_d=ltm->tm_mday;
QSSJ_h=ltm->tm_hour;
QSSJ_f=ltm->tm_min;
QSSJ_s=ltm->tm_sec;
QSSJ_SC = (((((QSSJ_y-100)*12+QSSJ_m)*31+QSSJ_d-1)*24+QSSJ_h)*60+QSSJ_f)*6
printf("11111111 InTime=[%s],qssj_sc=%ldrn",firsttime,QSSJ_SC);

ltm=localtime(&QSSJ_SC);
sprintf(firsttime, "%04d-%02d-%02d %02d:%02d:%02d",
ltm->tm_year+1900,
ltm->tm_mon+1,
ltm->tm_mday,
ltm->tm_hour,
ltm->tm_min,
ltm->tm_sec);
printf("22222222 InTime=[%s],qssj_sc=%ldrn",firsttime,QSSJ_SC);
运行结果为:
11111111 InTime=[20021215132903],qssj_sc=1035658399
22222222 InTime=[2002-10-27 02:53:19],qssj_sc=1035658399
为什么第二个时间是错的?

sprintf(tmp2,"20%02ld%02ld%02ld%02ld%02ld%02ld",
(QSSJ_SC/60L/60L/24L/31L/12L+100L)%100L,
QSSJ_SC/60L/60L/24L/31L%12L+1L,
QSSJ_SC/60L/60L/24L%31L+1L,
QSSJ_SC/60L/60L%24L,
QSSJ_SC/60L%60L,
QSSJ_SC%60L);
这样就解决问题了。

标签: